Re: How to discover foreign keys (without pulling hair out)

Hi,

I use pgAdminII on Windows. It connects to a PostgreSQL
on a Linux PC.
When you click on an existing table's icon, it shows you
a script that could have created it (it detects the
structure of the table by itself), including the foreign
keys.
That's an easy way. But maybe not very elegant...

-- Table: slip
CREATE TABLE "slip" (
"id_slip" int4 DEFAULT nextval
('"slip_id_slip_seq"'::text) NOT NULL,
"proprio" int4,
CONSTRAINT "slip_pkey" PRIMARY KEY ("id_slip"),
CONSTRAINT "slip_de" FOREIGN KEY ("proprio")
REFERENCES "maitre" ("maitre_id") ON DELETE NO ACTION ON
UPDATE NO ACTION NOT DEFERRABLE INITIALLY IMMEDIATE
);
COMMENT ON TABLE "slip" IS 'les slobards en folie !';
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On Thu, 25 Apr 2002, bob lapique wrote:

> I use pgAdminII on Windows. It connects to a PostgreSQL on a Linux PC.
> When you click on an existing table's icon, it shows you a script that
> could have created it (it detects the structure of the table by itself),
> including the foreign keys. That's an easy way. But maybe not very
> elegant...

I have in fact tried that very thing. pgAdminII has a Log View that is
supposed to show all the back-end SQL that it executes in order to show you
what it does. However, all it really does is retrieve the pg_triggers.tgargs
field, which is 6 fields separated by \0's, then it must parse it internally.

I'm looking for a way to parse 'one\000two\000three\000'::bytea into

foo1 | foo2 | foo3
------+------+-------
one | two | three

using only (Postgre)SQL, no external C functions or the like. Ideas? I'm
looking into PL/pgSQL as a solution, but haven't gotten very far yet.

Regards,
Ian Morgan
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