BUG #3487: regular exp

Lists: pgsql-bugs
From: "Mikhail" <Tuchkov(dot)Michail(at)gmail(dot)com>
To: pgsql-bugs(at)postgresql(dot)org
Subject: BUG #3487: regular exp
Date: 2007-07-26 05:53:54
Message-ID: 200707260553.l6Q5rsBr027947@wwwmaster.postgresql.org
Views: Raw Message | Whole Thread | Download mbox | Resend email
Lists: pgsql-bugs


The following bug has been logged online:

Bug reference: 3487
Logged by: Mikhail
Email address: Tuchkov(dot)Michail(at)gmail(dot)com
PostgreSQL version: 8.1
Operating system: windows 2003 SP2
Description: regular exp
Details:

Please, help me!
My code:
"IF char_length(substring(str from '^[a-zA-Z]*://'))=0 THEN
str:= 'http://'||str;
END IF;"

If str= http://www.msn.com then nothing happen
(all is OK), but if str= just www.msn.com then nothing happen too!

Why?

Then I experimen with that:
I change '=' to '<>'
results:
str=http://www.msn.com -> http://http://www.msn.com
str=www.msn.com -> http://www.msn.com

Thank you.


From: Magnus Hagander <magnus(at)hagander(dot)net>
To: Mikhail <Tuchkov(dot)Michail(at)gmail(dot)com>
Cc: pgsql-bugs(at)postgresql(dot)org
Subject: Re: BUG #3487: regular exp
Date: 2007-07-26 07:53:09
Message-ID: 20070726075309.GA22213@svr2.hagander.net
Views: Raw Message | Whole Thread | Download mbox | Resend email
Lists: pgsql-bugs

On Thu, Jul 26, 2007 at 05:53:54AM +0000, Mikhail wrote:
>
> The following bug has been logged online:
>
> Bug reference: 3487
> Logged by: Mikhail
> Email address: Tuchkov(dot)Michail(at)gmail(dot)com
> PostgreSQL version: 8.1
> Operating system: windows 2003 SP2
> Description: regular exp
> Details:
>
> Please, help me!
> My code:
> "IF char_length(substring(str from '^[a-zA-Z]*://'))=0 THEN
> str:= 'http://'||str;
> END IF;"
>
> If str= http://www.msn.com then nothing happen
> (all is OK), but if str= just www.msn.com then nothing happen too!
>
> Why?

Because substring() returns NULL when there is no match, not the empty
string. So you need
IF substring(str from '^[a-zA-Z]*://') IS NULL THEN
...

//Magnus