Lists: | pgsql-general |
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From: | "Uwe C(dot) Schroeder" <uwe(at)oss4u(dot)com> |
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To: | pgsql-general(at)postgresql(dot)org |
Subject: | SQL query question |
Date: | 2005-02-03 07:32:28 |
Message-ID: | 200502022332.28357.uwe@oss4u.com |
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Lists: | pgsql-general |
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Maybe it's to late for me to think correctly (actually I'm sure of that). I'm
going to ask anyways.
I have a table like
id int4
user_id int4
photo varchar
image_type char(1)
where image_type is either G or X
What I want to do is have ONE query that gives me the count of images of each
type per user_id.
So if user 3 has 5 photos of type G and 3 photos of type X
I basically want to have a result 5,3
It got to be possible to get a query like that, but somehow it eludes me
tonight.
Any pointers are greatly appreciated.
UC
- --
Open Source Solutions 4U, LLC 2570 Fleetwood Drive
Phone: +1 650 872 2425 San Bruno, CA 94066
Cell: +1 650 302 2405 United States
Fax: +1 650 872 2417
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From: | Jonel Rienton <jonel(at)road14(dot)com> |
---|---|
To: | "Uwe C(dot) Schroeder" <uwe(at)oss4u(dot)com> |
Cc: | Postgresql-General <pgsql-general(at)postgresql(dot)org> |
Subject: | Re: SQL query question |
Date: | 2005-02-03 08:31:28 |
Message-ID: | 7790df0d6e3c7934648612d461bb95a5@road14.com |
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Lists: | pgsql-general |
Hi Uwe,
I did a solution for you using PLPgSQL,
create or replace function countem() returns varchar as $$
declare
gcount integer;
xcount integer;
result varchar;
begin
select count(*) into gcount
from pix where image_type = 'G';
select count(*) into xcount
from pix where image_type = 'X';
select gcount || ', ' || xcount
into result;
return result;
end;
$$ LANGUAGE plpgsql;
hope this helps, it's simple and always, there's another (better)
solution
it's my first stab at plpgsql so please bear with me.
-----
Jonel Rienton
http://blogs.road14.com
Software Developer, *nix Advocate
On Feb 3, 2005, at 1:32 AM, Uwe C. Schroeder wrote:
> -----BEGIN PGP SIGNED MESSAGE-----
> Hash: SHA1
>
>
> Maybe it's to late for me to think correctly (actually I'm sure of
> that). I'm
> going to ask anyways.
> I have a table like
>
> id int4
> user_id int4
> photo varchar
> image_type char(1)
>
> where image_type is either G or X
> What I want to do is have ONE query that gives me the count of images
> of each
> type per user_id.
> So if user 3 has 5 photos of type G and 3 photos of type X
> I basically want to have a result 5,3
> It got to be possible to get a query like that, but somehow it eludes
> me
> tonight.
>
> Any pointers are greatly appreciated.
>
> UC
>
> - --
> Open Source Solutions 4U, LLC 2570 Fleetwood Drive
> Phone: +1 650 872 2425 San Bruno, CA 94066
> Cell: +1 650 302 2405 United States
> Fax: +1 650 872 2417
> -----BEGIN PGP SIGNATURE-----
> Version: GnuPG v1.2.3 (GNU/Linux)
>
> iD8DBQFCAdOMjqGXBvRToM4RApgvAJsEUsdl6hrVGqRwJ+NI7JrqQqQ5GgCgkTQN
> pavTkx47QUb9nr7XO/r/v5k=
> =B3DH
> -----END PGP SIGNATURE-----
>
>
> ---------------------------(end of
> broadcast)---------------------------
> TIP 2: you can get off all lists at once with the unregister command
> (send "unregister YourEmailAddressHere" to
> majordomo(at)postgresql(dot)org)
>
From: | Jonel Rienton <jonel(at)road14(dot)com> |
---|---|
To: | "Uwe C(dot) Schroeder" <uwe(at)oss4u(dot)com> |
Cc: | pgsql-general(at)postgresql(dot)org |
Subject: | Re: SQL query question |
Date: | 2005-02-03 08:36:00 |
Message-ID: | f6517db0a11905c3c4d98aa8ab889652@road14.com |
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Lists: | pgsql-general |
you're right it's late, i better to get to bed myself, i forgot to
throw in the parameter for the user_id in there, i'm sure you can
figure that one out.
regards,
-----
Jonel Rienton
http://blogs.road14.com
Software Developer, *nix Advocate
On Feb 3, 2005, at 1:32 AM, Uwe C. Schroeder wrote:
> -----BEGIN PGP SIGNED MESSAGE-----
> Hash: SHA1
>
>
> Maybe it's to late for me to think correctly (actually I'm sure of
> that). I'm
> going to ask anyways.
> I have a table like
>
> id int4
> user_id int4
> photo varchar
> image_type char(1)
>
> where image_type is either G or X
> What I want to do is have ONE query that gives me the count of images
> of each
> type per user_id.
> So if user 3 has 5 photos of type G and 3 photos of type X
> I basically want to have a result 5,3
> It got to be possible to get a query like that, but somehow it eludes
> me
> tonight.
>
> Any pointers are greatly appreciated.
>
> UC
>
> - --
> Open Source Solutions 4U, LLC 2570 Fleetwood Drive
> Phone: +1 650 872 2425 San Bruno, CA 94066
> Cell: +1 650 302 2405 United States
> Fax: +1 650 872 2417
> -----BEGIN PGP SIGNATURE-----
> Version: GnuPG v1.2.3 (GNU/Linux)
>
> iD8DBQFCAdOMjqGXBvRToM4RApgvAJsEUsdl6hrVGqRwJ+NI7JrqQqQ5GgCgkTQN
> pavTkx47QUb9nr7XO/r/v5k=
> =B3DH
> -----END PGP SIGNATURE-----
>
>
> ---------------------------(end of
> broadcast)---------------------------
> TIP 2: you can get off all lists at once with the unregister command
> (send "unregister YourEmailAddressHere" to
> majordomo(at)postgresql(dot)org)
>
From: | Markus Schulz <msc(at)tastatur-junkie(dot)de> |
---|---|
To: | pgsql-general(at)postgresql(dot)org |
Subject: | Re: SQL query question |
Date: | 2005-02-03 11:48:36 |
Message-ID: | 200502031248.36407.msc@tastatur-junkie.de |
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Lists: | pgsql-general |
Am Donnerstag, 3. Februar 2005 08:32 schrieb Uwe C. Schroeder:
> Maybe it's to late for me to think correctly (actually I'm sure of
> that). I'm going to ask anyways.
> I have a table like
>
> id int4
> user_id int4
> photo varchar
> image_type char(1)
>
> where image_type is either G or X
> What I want to do is have ONE query that gives me the count of images
> of each type per user_id.
> So if user 3 has 5 photos of type G and 3 photos of type X
> I basically want to have a result 5,3
> It got to be possible to get a query like that, but somehow it eludes
> me tonight.
>
> Any pointers are greatly appreciated.
>
> UC
select user_id,image_type, count(id)
from <table>
group by user_id,image_type
should do it.
--
Markus Schulz
From: | Roman Neuhauser <neuhauser(at)chello(dot)cz> |
---|---|
To: | "Uwe C(dot) Schroeder" <uwe(at)oss4u(dot)com> |
Cc: | pgsql-general(at)postgresql(dot)org |
Subject: | Re: SQL query question |
Date: | 2005-02-03 12:37:54 |
Message-ID: | 20050203123754.GA10688@isis.wad.cz |
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Lists: | pgsql-general |
# uwe(at)oss4u(dot)com / 2005-02-02 23:32:28 -0800:
> -----BEGIN PGP SIGNED MESSAGE-----
> Hash: SHA1
>
>
> Maybe it's to late for me to think correctly (actually I'm sure of
> that). I'm going to ask anyways. I have a table like
>
> id int4
> user_id int4
> photo varchar
> image_type char(1)
>
> where image_type is either G or X
> What I want to do is have ONE query that gives me the count of images
> of each type per user_id.
> So if user 3 has 5 photos of type G and 3 photos of type X
> I basically want to have a result 5,3
SELECT COUNT(*) FROM t GROUP BY t.user_id, t.image_type
--
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