Re: generate_series to return row that doesn't exist in

On Fri, 2006-03-24 at 14:30, MaXX wrote:
> Hi,
>
> I have a table wich contains aggregated data,
> table stats_activity
> logtime timestamptz,
> count int
>
> given this dataset
> "2006-03-24 03:00:00+01";55
> "2006-03-24 04:00:00+01";33
> "2006-03-24 06:00:00+01";46
> "2006-03-24 07:00:00+01";63
> "2006-03-24 08:00:00+01";88
>
> I want to get this in order to plot the data
> "2006-03-24 03:00:00+01";55
> "2006-03-24 04:00:00+01";33
> >>"2006-03-24 05:00:00+01";0<<
> "2006-03-24 06:00:00+01";46
> "2006-03-24 07:00:00+01";63
> "2006-03-24 08:00:00+01";88
>
> I used generate_series to get all the timestamps I need but I don't know how
> to write my query.
>
>
> I've tried various combination of subselects, joins, union,... and I never
> managed to get the result I wanted... I'm sure the solution is trivial but I
> don't get it...
> I prefer to generate missing rows "on the fly" intead of actually storing
> useless data on the table.

More than likely you need a left join and a case statement.

select <selectlist>, case when a.date is null then 0 else a.date end
from (select * from generate_series() -- magic to get dates goes here)
as p left join maintable as a on (p.date=a.date);

There may be some small syntax error in there, as I've not tested it.
The relavent pages are:

case:
http://www.postgresql.org/docs/8.1/static/functions-conditional.html

joins:
http://www.postgresql.org/docs/8.1/static/queries-table-expressions.html