Re: extract or date_part on an interval? How many e

[Adrian Klaver <aklaver(at)comcast(dot)net>]

On Sunday 27 January 2008 6:30 pm, Bryce Nesbitt wrote:
> Hmm.  Seemed so simple.  But how do I get the number of years an
> interval represents?  extract is clearly the wrong way:
>
> stage=# select 'now()-'1987-02-01' as interval,extract(year from
> now()-'1987-02-01') as age;
>         interval          | age
> --------------------------+-----
> 7665 days 18:05:51.660345 |   0
>
> select EXTRACT(year FROM INTERVAL '7665 days'); gives the same result.
>
> select EXTRACT(day FROM now()-'1987-02-01')/365 as age; seems messy.
> select (now()-'1987-02-01')/365; gives extraneous junk.
>
>  Thanks!

SELECT age('1987-02-01'::timestamp);
           age
--------------------------
 20 years 11 mons 26 days
(1 row)

-- 
Adrian Klaver
aklaver(at)comcast(dot)net