Using distinct with sum()

[A Gilmore <agilmore(at)shaw(dot)ca>]

Hello,

I've trying to sum up distinct columns.  But it's summing them prior to 
the distinct taking effect.

--
CREATE TABLE t1 (
	id		integer,
	value1		integer,
	value2		integer,
	value3		integer
	);

INSERT INTO t1 (id,value1,value2,value3) VALUES (1,100,300,null);
INSERT INTO t1 (id,value1,value2,value3) VALUES (1,100,300,1);
INSERT INTO t1 (id,value1,value2,value3) VALUES (1,100,300,2);
INSERT INTO t1 (id,value1,value2,value3) VALUES (2,200,400,3);
INSERT INTO t1 (id,value1,value2,value3) VALUES (3,400,500,4);

SELECT DISTINCT id,value2 - value1 AS total FROM t1;

 id | total
----+-------
  1 |   200
  2 |   200
  3 |   100
--

Now what I'd like to do count(id) and sum(total)

--
SELECT DISTINCT count(id),sum(value2 - value1) AS total FROM t1;

 count | total
-------+-------
     5 |   900
--

I can get count() working how like by doing count(DISTINCT id) but how 
do I do get a query to produce the following output (count/sum 
post-distinct):

 count | total
-------+-------
     3 |   500

Thank you in advance,
- A Gilmore