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Re: How to obtain algebraic sum of equal lines



Ennio-Sr wrote:
Hi Oisin and Frank,

* Frank Bax <fbax(at)sympatico(dot)ca> [250406, 16:41]:
At 04:12 PM 4/25/06, Ennio-Sr wrote:

Hi all,
Is it possible, given the following table:

cod_rif | titolo | quantity |   cmf   |  u_qq  |  mont   | vend |  sum
---------+--------+----------+---------+--------+---------+------+-------
26      | aaa    |    -1000 | 6.11098 |  6.176 |  6.1110 | t    | -1000
7       | aaa    |     2500 |  25.455 |      0 | 60.0897 | f    |  2500
28      | bbb    |     2700 |   3.862 |    4.6 |  4.1957 | f    |  2700
3       | bbb    |      500 |   6.057 | 10.129 | 18.7311 | f    |   500
34      | bbb    |     -700 |       0 |      0 |  0.0000 | t    |  -700
6       | bbb    |     -500 |   2.703 |  4.757 |  3.7151 | f    |  -500
30      | ccc    |     5000 |   1.717 |  1.489 |  1.7170 | f    |  5000
33      | ccc    |    10000 |    4.36 |      0 |  4.3600 | f    | 10000
11      | ddd    |    -1500 |  10.537 |  4.021 | 20.5815 | t    | -1500
32      | ddd    |     1500 | 0.55896 |  1.119 |  0.5590 | f    |  1500
(10 rows)

to get a selection whereby the algebraic sum of "quantity" for each equal 'titolo'
is returned?

I tried this query with no result:
psql finanza -c "select * , (sum(quantity)) from test_t group by cod_rif, titolo, quantity, cmf, u_qq, mont, vend order by titolo asc"
psql finanza -c "select titilo, (sum(quantity)) from test_t group by titolo order by titolo asc"


The point is that command would return two cols only, whereas I would
like to have all the cols, like:

 26      | aaa    |     1500 | 6.11098 |  6.176 |  6.1110 | t    |  1500
 28      | bbb    |     2000 |   3.862 |    4.6 |  4.1957 | f    |  3200

i.e. aaa=(-1000+2500=1500), bbb=(2700+500-700-500)=2000
which, I fear, is not possible ;-(

select *,(select sum(quantity) from test_t t2 where t2.titolo=t1.titolo) as sum from test_t t1;

would do it though who knows how inefficient this is?

Oisin




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