Re: How to obtain algebraic sum of equal lines
Ennio-Sr wrote:
Hi Oisin and Frank,
* Frank Bax <fbax(at)sympatico(dot)ca> [250406, 16:41]:
At 04:12 PM 4/25/06, Ennio-Sr wrote:
Hi all,
Is it possible, given the following table:
cod_rif | titolo | quantity | cmf | u_qq | mont | vend | sum
---------+--------+----------+---------+--------+---------+------+-------
26 | aaa | -1000 | 6.11098 | 6.176 | 6.1110 | t | -1000
7 | aaa | 2500 | 25.455 | 0 | 60.0897 | f | 2500
28 | bbb | 2700 | 3.862 | 4.6 | 4.1957 | f | 2700
3 | bbb | 500 | 6.057 | 10.129 | 18.7311 | f | 500
34 | bbb | -700 | 0 | 0 | 0.0000 | t | -700
6 | bbb | -500 | 2.703 | 4.757 | 3.7151 | f | -500
30 | ccc | 5000 | 1.717 | 1.489 | 1.7170 | f | 5000
33 | ccc | 10000 | 4.36 | 0 | 4.3600 | f | 10000
11 | ddd | -1500 | 10.537 | 4.021 | 20.5815 | t | -1500
32 | ddd | 1500 | 0.55896 | 1.119 | 0.5590 | f | 1500
(10 rows)
to get a selection whereby the algebraic sum of "quantity" for each equal
'titolo'
is returned?
I tried this query with no result:
psql finanza -c "select * , (sum(quantity)) from test_t group by cod_rif,
titolo, quantity, cmf, u_qq, mont, vend order by titolo asc"
psql finanza -c "select titilo, (sum(quantity)) from test_t group by
titolo order by titolo asc"
The point is that command would return two cols only, whereas I would
like to have all the cols, like:
26 | aaa | 1500 | 6.11098 | 6.176 | 6.1110 | t | 1500
28 | bbb | 2000 | 3.862 | 4.6 | 4.1957 | f | 3200
i.e. aaa=(-1000+2500=1500), bbb=(2700+500-700-500)=2000
which, I fear, is not possible ;-(
select *,(select sum(quantity) from test_t t2 where t2.titolo=t1.titolo)
as sum from test_t t1;
would do it though who knows how inefficient this is?
Oisin
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