Re: sum() over (partition by order) question

["Pavel Stehule" <pavel(dot)stehule(at)gmail(dot)com>]

2008/12/31 Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us>:
> "Pavel Stehule" <pavel(dot)stehule(at)gmail(dot)com> writes:
>> so I have to modify query to get expected values
>> postgres=# select a, b, last_value(a) over (partition by b),
>> last_value(a) over (partition by b order by a  RANGE BETWEEN UNBOUNDED
>> PRECEDING AND UNBOUNDED FOLLOWING) from foo;
>
>> it should be noticed in doc?
>
> It is --- see the comments at the bottom of
>
> http://developer.postgresql.org/pgdocs/postgres/functions-window.html
>
>                        regards, tom lane
>

there is maybe bug. It works well with explicit definition, but it not
works when I will window
good
postgres=# select a, b, sum(a) over (partition by b order by a ROWS
BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) from foo;
 a  | b | sum
----+---+-----
  1 | 1 |  19
  1 | 1 |  19
  2 | 1 |  19
  2 | 1 |  19
  4 | 1 |  19
  4 | 1 |  19
  5 | 1 |  19
 11 | 3 |  93
 12 | 3 |  93
 16 | 3 |  93
 16 | 3 |  93
 16 | 3 |  93
 22 | 3 |  93
(13 rows)

wrong
postgres=# select a, b, sum(a) over (w) from foo window w as
(partition by b order by a ROWS BETWEEN UNBOUNDED PRECEDING AND
UNBOUNDED FOLLOWING);
 a  | b | sum
----+---+-----
  1 | 1 |   2
  1 | 1 |   2
  2 | 1 |   6
  2 | 1 |   6
  4 | 1 |  14
  4 | 1 |  14
  5 | 1 |  19
 11 | 3 |  11
 12 | 3 |  23
 16 | 3 |  71
 16 | 3 |  71
 16 | 3 |  71
 22 | 3 |  93
(13 rows)

regards
Pavel Stehule