Return rows from function with expressions
- From: novnov <novnovice(at)gmail(dot)com>
- To: pgsql-general(at)postgresql(dot)org
- Subject: Return rows from function with expressions
- Date: Thu, 24 May 2007 13:59:24 -0700 (PDT)
- Message-id: <10792602(dot)post(at)talk(dot)nabble(dot)com>
I've written many stored procedures in ms sql and a good many functions in
postgres, but I'm rather unsure of how to get a list back from a postgres
function which is not based on a table. Example from sql server:
set ANSI_NULLS ON
set QUOTED_IDENTIFIER ON
GO
ALTER PROCEDURE [dbo].[procPatient]
@PatStatusID int = 0
AS
BEGIN
SELECT PatID, PatFName + ' ' + PatLName as pname FROM tblPatient WHERE
PatStatusID = @PatStatusID
END
Output from the sproc above is like
PatID pname
123 Merton Baffled
129 Jim Puzzled
I've spent a good deal of time reading here and in the pg docs about
functions that use SETOF. I can't find a plain and simple way to do
something like the above. Is there? I simply need to pass in some params,
and do some evals inside the function and return a set that includes some
cols that are not part of the base table. I've seen solutions that involve
OUT params; a method which uses RECORD that requires the columns to be
defined in the call; refcursors (which I don't really understand); are those
the only options? A simple example like the one I've used for sql server
above would be ideal.
--
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